Question

Find the equation of the line which passes through (4,1) and is parallel to the line with equation 2y=x+1

Answer 1

Parallel to the line:

`{\sf{2y = x + 1}}`

`{\sf{y = (x)/(2) + (1)/(2 )}}`

Hence Slope:

`{\sf{\large{(1)/(2)}}}`

The slope of line of which equation we need is parallel to the line given. Therefore, it's slope also is (m):

`{\sf{\large{(1)/(2)}}}`

Also, the line passes through the points (4, 1)

Therefore by the formula of

`{\sf{(y - y1) = m(x - x1)}}`

we have:

`{\sf{(y - 1) = (1)/(2) (x - 4) }}`

`{\sf{2y - 2 = x - 4}}`

`{\sf{x - 4 - 2y + 2 = 0}}`

`{\sf{\red{\boxed{\sf{x - 2y - 2 = 0}}}}}`