Question

An open train car, with a mass of 2010 kg, coasts along a horizontal track at the speed 2.53 m/s. The car passes under a loading chute and, as it does so, gravel falls vertically into it for 3.25 s at the rate of 423 kg/s. What is the car's speed ????f after the loading is completed? Ignore rolling friction.

Answer 1

v' = 1.5 m/s

Step-by-step explanation:

Given that,

Mass of the car, m = 2010 kg

Speed of the car, v = 2.53 m/s

The car passes under a loading chute and gravel falls vertically into it for 3.25 s at the rate of 423 kg/s. Mass loaded during this time, m' = 1374.75 kg

Let v' is the speed of car after the loading is completed. Using the conservation of momentum to find it.

`mv=(m+m')v'`

`v'=(mv)/(m+m')`

`v'=(2010* 2.53)/(2010+1374.75)`

v' = 1.5 m/s

So, the speed of the car after the loading is completed is 1.5 m/s. Hence, this is the required solution.