Answer:
I = 578A
Step-by-step explanation:
The magnitude of the peak value of the induced current flowing in a coild is given by
![I = (\epsilon_(max))/(R)](https://img.qammunity.org/2020/formulas/physics/college/g0ley3srj3lotzegf0h4yapytdzvrtjp58.png)
![I = (NBA\omega)/(R)](https://img.qammunity.org/2020/formulas/physics/college/ej245p1t5bdqdc5bassx58152ap21xmroq.png)
Where
I= current
N = Number of loops
angular velocity
R= Resistance
B = Magnetic field
A = Area
Replacing our values we have that,
![I = ((100)(1.3)(0.055)^2(2.5))/(1.7*10^(-3))](https://img.qammunity.org/2020/formulas/physics/college/nc9fr1u4euc3ok907t0xz2mt1cjncln367.png)
![I = 578A](https://img.qammunity.org/2020/formulas/physics/college/bs0k5f5c19bsdikl26fy3j67wmiz4ixdot.png)