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Suppose we are given a square coil that is 5.5 cm on a side containing 100 loops of very fine wire. The total resistance of this coil is 1.7 ✕ 10−3 Ω. This coil is initially centered on the origin with its sides parallel to the x- and y-axes. It is being rotated about the y-axis in a uniform magnetic field of 1.3 T along the z-axis, with an angular velocity of 2.0 rad/sec. Find the magnitude of the peak value of the induced current flowing in this coil under these conditions.

User Antonio MG
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1 Answer

6 votes

Answer:

I = 578A

Step-by-step explanation:

The magnitude of the peak value of the induced current flowing in a coild is given by


I = (\epsilon_(max))/(R)


I = (NBA\omega)/(R)

Where

I= current

N = Number of loops


\omega = angular velocity

R= Resistance

B = Magnetic field

A = Area

Replacing our values we have that,


I = ((100)(1.3)(0.055)^2(2.5))/(1.7*10^(-3))


I = 578A

User Johnie Karr
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