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Find an equation for the line graphed below:

Find an equation for the line graphed below:-example-1
User Brooks DuBois
by
2.9k points

2 Answers

15 votes
15 votes

Answer:

Answer given by bryc31 is correct:
y = -(1)/(5)x -3 is correct

I am simply providing an explanation in case you need it

Explanation:

The slope-intercept form equation of a straight line in 2D coordinates is given by y = mx + b

where m is the slope(rise/run) and b the y-intercept i.e. the y value where the line intersects the y axis

Given two points (x₁, y₁) and (x₂, y₂) on the straight line, we can compute the slope as follows

m =
(y_2 - y_1)/(x_2-x_1)

Two distinct points on the line are at (0, -3) and (5,-4)


m = (-4 -(-3))/(5-0) = (-4 + 3))/(5-0) = (-1)/(5) = - (1)/(5)

So we know the equation to be


y = - (1)/(5)x + b

To find b, take any point on the straight line, plug in y and x values in the above equation and solve for b

However, looking at the graph we see that the line crosses the y axis at

y = -3. So this is the value for the y intercept i.e. b

The equation of the line is therefore


y = - (1)/(5)x - 3

User Pwolaq
by
3.1k points
22 votes
22 votes

Answer: y = -1/5x -3

Explanation:

User Swing
by
3.3k points