Answer:
Horizontal component of the initial velocity=v ×cos20°
horizontal displacement= 35m
time taken. (t)=35÷(v×cos20°)
vertical component of the initial velocity= v×sin20°
vertical displacement= -5m(since it is opposite to the direction of the initial velocity. )
application of s=ut+1/2at×t. vertically,
-5=vsin20°×t -1/2 gt×t
-5= vsin20×35/vcos20-1/2×10×35×35/(vcos20×vcos20)
simplify further to obtain v and hence find the time taken