Question

What is the equation, in point-slope form, of the line that is

perpendicular to the given line and passes through the
point (-4, -3)?
y + 3 = -4(x + 4)
y + 3 = 7 (x+4)
y + 3 = 7/(x + 4)
y + 3 = 4(x + 4)

Answer 1

`y+3=(1)/(4)(x+4)`

Explanation:

The slope of given line is:

`\text{Slope}=(1-(-3))/(-1-0)=-4\\</p><p>\text{Let slope of perpendicular line be= m}\\</p><p>\implies m* (-4)=(-1)\implies m=(1)/(4)\\</p><p>\text{Thus the required equation:}\\</p><p>(y-(-3))=(1)/(4)(x-(-4))\\</p><p>(y+3)=(1)/(4)(x+4)\\`