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Evaluate the limit of the following.
(1/n)(sin(n*pi/2))

User Sjbuysse
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1 Answer

3 votes


(\pi)/(2)

Explanation:

When
n->0 ,
(Sin(kn))/(n)->k

This is because,

using l'hospital's rule,
Lt_(n->0)(sin(kn))/(n)=(kcos(n))/(1) =(k* 1)/(1) =k

In the given question,
k=(n*\pi)/(2)

So,the given limit evaluates to
(n\pi)/(2)

User Nikhil Katekhaye
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