Question

Playing shortstop, you pick up a ball and throw it to second base. The ball is thrown horizontally, with a speed of 21m/s, directly towards point A. When the ball reaches the second baseman 0.46 s later, it is caught at point B. Part A.) how far were you from the second baseman? Part B.) What is the distance of vertical drop, from A to B

Answer 1

distance to second baseman = 9.66 m

vertical drop = 1.058m

Step-by-step explanation:

A) applying motion equation to horizontal motion

(assuming no acceleration in horizontal motion)

distance to second baseman = velocity * time

= 21 * 0.46

= 9.66 m

B) applying motion equation to vertical motion

(starting velocity was horizontal. therefore no vertical component. subjected to gravity ,g=10m/s2)

`s=ut+(1)/(2) *at^(2) \\=0+(1)/(2)*10*0.46^(2)  \\=1.058 m`

vertical drop = 1.058m