Question

class size m average 0.82 n class n average 0.78. if the average for combined classes is 80%, what is relationship between m and n?​

Answer 1

The relation between m and n is , m = n

Explanation:

Given as :

The average for n class = 0.82 = 82%

The average for m class = 0.78 = 78%

The average for ( m + n ) class = 80%

So ,
`(x_1 +x_2+x_3+x_4+ ....... + x_n)/(n)` = 82%

And
`(x_1 +x_2+x_3+x_4+ ....... + x_m)/(m)` = 78%

And ,
`((x_1+x_2+x_3+x_4+ ......+x_n ) + (x_1+x_2+x_+x_4+.....+x_m))/(m+n)` = 80%

So , 0.82×n + 0.78×m = 0.80× (m+n)

Or, 0.82×n - 0.80×n = 0.80×m - 0.78×m

Or, 0.02×n = 0.02×m

Or,
`(m)/(n)` =
`(0.02)/(0.02)`

∴
`(m)/(n)` = 1

I.e m = n

Hence The relation between m and n is , m = n Answer