The length and width of the rectangle are 19 inches and 13 inches respectively.
Solution:
Given that , A rectangular sheet of metal has an area of 247 square inches. Its perimeter is 64 inches.
Let the length of rectangle be a and width of rectangle be b.
The area of rectangle is given as:
![area = length * width](https://img.qammunity.org/2020/formulas/mathematics/middle-school/anczz5q40m4ru7swbq81n5ra371p0mnmy3.png)
![\text { Then, area } \rightarrow a b=247](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cnnb59v79gdprj7il2vsnahlub2kwcvpvd.png)
The perimeter of rectangle is given as:
Perimeter = 2(length + width)
Then 2(a + b) = 64
a + b = 32 ⇒ (1)
![\begin{array}{l}{\text { Now we know that, }(a-b)^(2)=(a+b)^(2)-4 a b} \\\\ {\text { Then, }(a-b)^(2)=32^(2)-4 * 247} \\\\ {(a-b)^(2)=1024-988} \\\\ {a-b=√(36)}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ih7fjutqjdcmce3ybkarnw8uyklisd2k3l.png)
a – b = 6 ---- (2)
Now solve (1) and (2)
2a = 38
a = 19
Then, 19 + b = 32
b = 32 – 19 = 13
hence, the length and width of the rectangle are 19 inches and 13 inches respectively.