Answer:
2.047 × 10^24 atoms
Step-by-step explanation:
- We need to know that 1 mole of an element contains atoms equivalent to the Avogadro's constant.
- The Avogadro's constant is 6.022 × 10^23.
- Therefore, 1 mole of Fe contains 6.022 × 10^23 atoms.
In this case we are given 3.4 moles of Iron.
we are required to find the number of atoms in 3.4 moles.
Therefore, since 1 mole of Fe contains 6.022 × 10^23 atoms.
Then, 3.4 mole will contain;
= 3.4 moles × 6.022 × 10^23 atoms/mole
= 2.047 × 10^24 atoms
Thus, 3.4 moles of Iron contains 2.047 × 10^24 atoms