Question

7. The area of a parallelogram is 8V90 and the base is 2V5. What is the

height of the parallelogram?

Answer 1

Height is
`12√(2)`.

Explanation:

Given:

Area of the parallelogram is,
`A=8√(90)`

Base of the parallelogram is,
`b=2√(5)`

Let
`h` be the height.

Therefore, area of the parallelogram is given as:

`A=b* h\\8√(90)=2√(5)* h\\h=(8√(90))/(2√(5))\\h=4\sqrt{(90)/(5)}\\h=4√(18)\\h=4√(2* 9)\\h=4* 3√(2)=12√(2)`

Therefore, the height of the parallelogram is
`12√(2)`.