Answer:
Power input is 125 W.
Step-by-step explanation:
Given:
Force applied for lifting the barbell,
![F=100\textrm{ N}](https://img.qammunity.org/2020/formulas/physics/middle-school/ebbyt7wdp16shhxqfssm0b182zchn6g3x5.png)
Displacement caused by the force,
![S=2.5\textrm{ m}](https://img.qammunity.org/2020/formulas/physics/middle-school/8j89lvtdqzug4kaob397ylqavuo8e9l3rc.png)
Time taken for the lift,
![t=2\textrm{ s}](https://img.qammunity.org/2020/formulas/physics/middle-school/bnhuy8joi5mbaio4npudtfya7au8tdom6k.png)
Work done by the weightlifter in raising the barbell is given as,
![Work=Force* displacement\\Work=100* 2.5\\Work=250\textrm{ J}](https://img.qammunity.org/2020/formulas/physics/middle-school/21iqvhol7j0i3p0xttthx2u8wy9tzlohou.png)
Now, power input is given as,
![Power=(Work)/(Time)\\\\Power=(250)/(2)=125\textrm{ W}](https://img.qammunity.org/2020/formulas/physics/middle-school/pdol3ys5akqvwb436ovpyq6ovwth2bqimq.png)
Therefore, the power input is 125 watts.