The linear equation is y = (1/3)*x - 4
How to write the equation?
Two lines are parallel if the slope is the same, here we want a line parallel to:
3y - x =-12
3y = x - 12
y = (1/3)*x - 4
The slope is (1/3), so we want a line of the form:
y = (1/3)*x + b
This line must pass trough (18, 2), then we can replace the values:
2 = (1/3)*18 + b
2 = 6 + b
2 - 6 = b
-4 = b
The line is y = (1/3)*x - 4