Answer:
.70 g of water will be formed.
Step-by-step explanation:
NaOH + HBr = NaBr + H₂O
40 g 103 g 18 g
40 g of sodium hydroxide reacts with 103 g of HBr
2.6 g of sodium hydroxide reacts with 103 x 2.6 / 40 = 6.7 g of HBr
4.05 g of HBr is available so HBr is limiting reagent .
103 g of HBr reacts with NaOH to form 18 g of water
4.05 g of HBr reacts with NaOH to form 18 x 4.05 / 103 g
= .70 g of water will be formed.