Question

the length of the rectangle is twice its width. write and solve a system of linear equations to find the length L and width W of the rectangle... The perimeter is 36 ft​

Answer 1

2 ( m + 2 m) = 36 is the required linear equation

Length of the rectangle is 12 ft and width = 6 ft

Explanation:

Let the width of the rectangle = m ft.

So, the length of the rectangle = 2m ft.

Perimeter of rectangle = 36 ft

Now, PERIMETER OF THE RECTANGLE = 2(LENGTH + WIDTH)

⇒2 ( m + 2m) = 36

or, 2 x 3m = 36

⇒ 6m = 36 , or m = 36/6

⇒ m =6 ft

So, the Width of the rectangle; = m = 6 ft

and the Length of the rectangle = 2 m = 2 x 6 = 12 ft.