Question

Calculate the average rate of decomposition of NH4NO2 by the reaction 2NH4O5(aq) --> N2(g) H2O(g) at the following time interval. At time 250 s, the concentration of NH4NO2 is 4.12 M. At time 330 s, the concentration of NH4NO2 is 1.48 M

Answer 1

`r=-0.033(M)/(s)`

Step-by-step explanation:

Hello!

In this case, since the average rate of reaction is computed as a change given by:

`r=(\Delta [NH_4NO_2 ])/(\Delta t)`

In such a way, given the concentrations at the specified times, we plug them in to obtain:

`r=((1.48M-4.12M))/((330s-250s))\\\\r=-0.033(M)/(s)`

Whose negative sign means the concentration decreased due to the decomposition.

Best regards!