Answer:
the volume that has 1.0m^2 of water from the surface of the lake is 4.3
Step-by-step explanation:
The computation of the volume is as follows;
The Bulk modulus is
= K = 2.3 × 10^9 Pa
K = - V dP ÷ dV
dV = - V dP ÷ K
dV = - (1 × 101.3 × 1000) ÷ 2.3 × 10^9
= - 4.3 × 10^-3 m^3
So the volume that has 1.0m^2 of water from the surface of the lake is 4.3
Hence the same is relevant and considered