Question

X(t) = 20-4t²
then what is average Velocity
in between t= 0 and t=20sec​

Answer 1

v = -80 m/s

Step-by-step explanation:

Given,

The initial time of a body, t = 0

The final time of the body, t =20 s

The displacement function of the body is given by the relation,

X(t) = 20 - 4t²

Therefore, the velocity function is by differentiating the above equation with respect to the function 't'

X'(t) = -8t²

Then,

1) t = 0 s

X'(0) = -8(0)²

= 0 m/s

2) t = 20 s

X'(20) = -8(20)²

= -160 m/s

The average velocity is given by averaging the initial and final velocity,

V = -160/2

= -80 m/s

Hence, the average velocity of the given function is, v = -80 m/s