Answer:
1.66x10⁶kJ of energy are produced
Step-by-step explanation:
...Produces 45kJ... Has a density of 0.77g/mL... By burning 48L of gasoline...
To solve this question we need to calculate the mass in grams of gasoline in 48L using its density.
With the mass and knowing 1gram produces 45kJ of energy we can find the energy produced by burning 48L of gasoline, thus:
mL of gasoline:
48L * (1000mL / 1L) = 48000mL of gasoline
g of gasoline:
48000mL * (0.77g/mL) = 36960g of gasoline
Energy produced:
36960g of gasoline * (45kJ / g) =
1.66x10⁶kJ of energy are produced