Question

Can someone help me with this molar mass problem?[It’s the last one]

Answer 1

`54.18 * 10^(23) \ moles` in 3 mole of
`Al_2(SO_4)_3`

Step-by-step explanation:

It is clear that in the given
`1\ mole` of
`Al_2(SO_4)_3` have
`3\ ions` of
`SO_4^2^-`

Therefore 3 moles of
`Al_2(SO_4)_3` will have
`3*3=9 \ ions` of
`SO_4^2^-`

Since 1 ion of anything is equivalent to
`6.02*10^(23) \ moles`

Therefore 3 moles of
`Al_2(SO_4)_3` will have
`3*3=9 \ ions` of
`SO_4^2^-`

Which is equivalent to
`9 *6.02*10^(23)=54.18*10^(23) \ moles`

Thus 3 moles of
`Al_2(SO_4)_3` gives
`54.18*10^(23) \ moles` of
`SO_4^2^-`.