Question

Ask Your Teacher Sodium hydroxide solution is usually standardized by titrating a pure sample of potassium hydrogen phthalate (KHC8H4O4, often abbreviated KHP), an acid with one acidic hydrogen and a molar mass of 204.220 g/mol. It takes 36.01 mL of a sodium hydroxide solution to titrate a 0.1182-g sample of KHP. What is the molarity of the sodium hydroxide

Answer 1

0.0161 M

Step-by-step explanation:

Moles of KHP :

Given, Mass of KHP = 0.1182 g

Molar mass of KHP = 204.22 g/mol

The formula for the calculation of moles is shown below:

`moles = (Mass\ taken)/(Molar\ mass)`

Thus,

`Moles= (0.1182\ g)/(204.22\ g/mol)`

`Moles\= 5.7879* 10^(-4)\ mol`

According to the reaction shown below:

KHP + NaOH ⇒ KNaP + H₂O

1 mole of KHP reacts with 1 mole of NaOH

So,

`5.7879* 10^(-4)\ mol` of KHP reacts with
`5.7879* 10^(-4)\ mol` of NaOH

Moles of NaOH =
`5.7879* 10^(-4)\ mol`

Volume = 36.01 mL = 0.03601 L ( 1 mL = 0.001 L)

`Molarity=(Moles\ of\ solute)/(Volume\ of\ the\ solution)`

`Molarity_(NaOH)=(5.7879* 10^(-4))/(0.03601 L)`

`Molarity_(NaOH)=0.0161\ M`