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What is the molarity of a 0.40 L Solution with 6.2 g KCl?

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Answer:

Molarity of KCl = 0.03M

Step-by-step explanation:


Molarity=(W)/(GMW) * (1000)/(V(in\,ml))

Given

Weight of
$KCl$
=6.2g


V=0.40 L=400ml

Gram Molecular weight
=74.55g


Therefore Molarity = (6.2)/(74.55)*{1000}{400}\\                                =0.03M

User Denis Olifer
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