Question

A bucket of water with total mass 24 kg is attached to a rope, which in turn is wound around a 0.04-m radiuscylinder at the top of a well. The bucket is raised to the top of the well and released. The bucket is moving with aspeed of 4.0 m/s upon hitting the water surface in the well. What is the angular speed of the cylinder at thisinstant?

Answer 1

Angular speed,
`\omega=100\ rad/s`

Step-by-step explanation:

Given that,

Total mass of the bucket, m = 24 kg

Radius of the cylinder, r = 0.04 m

Speed of the bucket, v = 4 m/s

To find,

The angular speed of the cylinder at this instant

Solution,

The relation between the linear speed and the angular speed is given by :

`v=r* \omega`

`\omega=(v)/(r)`

`\omega=(4\ m/s)/(0.04\ m)`

`\omega=100\ rad/s`

Therefore, the angular speed of the cylinder at this instant is 100 rad/s.