Answer: 76.3 ° C
Step-by-step explanation:
Outside Distance = 10 m
Outside diameter, d = 2.2 m
R=D/2 = 2.2/2= 1.1 m
inner radius, Rs = = 1.1 m
Surface Temperature Ts = 20°C
Given that the thermal conductivity of soil, K = 0.52 W/mK
We can find the outside temperature of the container by finding the thermal temperature of conductor, T, and then summing up with the surface temperature
That is (T + Ts)
we know amount of heat, Q is given by :
Q = [(T-Ts) / (R- Rs)/4πKRRs
500 = T-20 [4π×0.52×1.1×10] / (10-1.1)
500= T-20 (71.88/8.9)
500 = T-20 (8.08)
500 = 8.08T - 161.6
8.08T = 500 + 161.6
8.08T = 661.6
T = 76.33 ° C