Answer:
p = 32.32; A = 47.91
Explanation:
1. Calculate ∠B
∠A + ∠B + ∠C = 180°
60° + ∠B + 45° = 180°
∠B + 105° = 180°
∠B = 75°
2. Find sides BC and AC
We can use the Law of Sines
![(\sin A)/(BC) = (\sin B)/(AC) = (\sin C)/(AB)](https://img.qammunity.org/2020/formulas/mathematics/high-school/jw8yon3ida8n51lsudbo40z8f8ac41f330.png)
(i) Find BC
![(\sin 75^(\circ))/(AC) = (\sin 45^(\circ))/(9)\\\\(0.8660)/(BC) = (0.7071)/(9)\\\\BC = 9 * (0.8661)/(0.7071) = 11.02](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4is0bzvb21a8vm1jmktz1av2cyyffrknz2.png)
(ii) Find AC
![(\sin 75^(\circ))/(AC) = (\sin 45^(\circ))/(9)\\\\(0.9659)/(AC) = (0.7071)/(9)\\\\BC = 9 * (0.9659)/(0.7071) = 12.29](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a6fst5ahaqxjb3hfoomu432wjg5f5746ku.png)
3. Find the perimeter
p = AB + AC + BC = 9 + 12.29 + 11.02 = 32.32
4. Find the area of the triangle
A general formula for the area of a triangle is
A = ½ab sinC
If we use ∠A, the formula becomes
A = ½ × 9 × 12.29 × sin60° = 55.30 × 0.8660 = 47.91