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A space probe is traveling in outer space with a momentum that has a magnitude of 5.92 x 107 kg·m/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 1.91 x 106 N and a direction opposite to the probe's motion. It fires for a period of 10.4 s. Determine the momentum of the probe after the retrorocket ceases to fire.

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Answer:


p_f=7.90* 10^7\ kg.m/s

Step-by-step explanation:

Given that,

Initial momentum of the probe,
p_i=5.92* 10^7\ kg.m/s

Applied force to the probe,
F=1.91* 10^6\ N

Time period, T = 10.4 s

To find,

Final momentum of the probe.

Solution,

We know that according to the impulse- momentum theorem, the impulse is equal to the change in momentum. Mathematically, it is given by :


F\Delta t=p_f-p_i


p_f=F\Delta t+p_i


p_f=1.91* 10^6* 10.4+5.92* 10^7


p_f=7.90* 10^7\ kg.m/s

Therefore, the momentum of the probe after the retrorocket ceases to fire is
7.90* 10^7\ kg.m/s. Hence, this is the required solution.

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