Answer:
EF = BC = a ÐF is a right angle. FD = CA = b triangle EF = BC = a angle F is a right angle. FD = CA = b In triangle DEF, By Pythagoras Theorem, a2 + b2 = c2 the given AB=c= a^2 + b^2 square root Theorefore AB = DE But by construction, BC = EF and CA = FD triangle ABC congruent to DEF (S.S.S
We have given that Δ ABC is similar to Δ CBD and Δ ABC is similar to Δ ACD according to the attached picture.
Because of the similarity the corresponding sides are proportional. Then a/c = f/a
and b/e = c/b. If we cross multiply, we'll get
a² = cf and b² = ce
If we add these equalities together, we'll get
a² + b² = c (f + e)
From the beginning, we know that c = e+f
Then, the final result is:
a² + b² = c²