Question

Children slide down a frictionless water slide that ends at a height of 1.80 m above the pool. If a child starts from rest at point A and lands in the water at point B, a horizontal distance L = 3.55 m from the base of the slide, determine the height h of the water slide.

Answer 1

`h = 1.75 m`

Step-by-step explanation:

As we know that height of the slide is given as

`h = 1.80 m`

so time taken by the child to hit the water from the slide is given as

`t = \sqrt{(2h)/(g)}`

now we will plug all data in it

`t = \sqrt{(2(1.80))/(9.81)}`

`t = 0.605 s`

now we know that the horizontal distance moved by it is given as

`L = v_x t`

`3.55 = 0.605 v_x`

`v_x = 5.86 m/s`

now by energy conservation

`mgh = (1)/(2)mv^2`

so height of point A is given as

`h = (v_x^2)/(2g)`

`h = (5.86^2)/(2(9.81))`

`h = 1.75 m`