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In a shipment of 11 CD​ players, two are defective. Find the probability that a sample of 3 CD players will not contain any that are defective.

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Answer:

54.8%

Explanation:

P = nCr pʳ qⁿ⁻ʳ

P = ₃C₀ (2/11)⁰ (9/11)³

P = 0.548

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