Question

Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(3, -2), B(6, -2), C(6, 5), and D(3, 5). What is the area of rectangle ABCD?

Answer 1

`21\ un^2.`

Explanation:

Rectangle ABCD with vertices A(3, -2), B(6, -2), C(6, 5), and D(3, 5) is graphed in the coordinate plane.

Sides AB and CD are parallel to the x-axis and sides AD and BC are parallel to the y-axis.

So,

`\text{Width}=AB=|6-3|=3\\ \\\text{Length}=AD=|5-(-2)|=7`

The area of the rectangle is

`A_(ABCD)=\text{Width}\cdot \text{Length}\\ \\A_(ABCD)=3\cdot 7=21\ un^2.`