Question

A man applies a torque to a nut with a wrench 0.350 m long. Because of the cramped space, he must exert a force upward at an angle of 62.0° with respect to a line from the nut through the end of the wrench. If the force he exerts has magnitude 52.0 N, what magnitude torque (in N · m) does he apply to the nut? (Assume that the force is applied at the end of the wrench.)

Answer 1

`T= 16.07N.m`

Step-by-step explanation:

It is a problem to find the torque but the force applied was performed angularly. In this way the only component that will serve us is the one found in the line of rotation of the object.

`Lenght (l) = 0.350m\\Force (F) = 52N\\Angle (\theta) = 62.0\°`

Since the force is realized from upward with respect to a line from the bolt through the end of the wrench, we have the component described by Sin (\ theta). The force is performed on the opposite side of the angle, then

`T=(F)(l)Sin\theta= 52*0.350*Sin62`

`T= 16.07N.m`