Answer:
Explanation:
The total number of operations prepared by the surgeon is X.
The questions can be solved by set
For two sets A and B,
Where A= The surgery done with infections
B= Surgery done which failed
n(AᴜB) is the number of elements present in either of the sets A or B.
n(A∩B) is the number of elements present in both the sets A and B.
Y= number of surgery which succeed and are free from infection
n(AᴜB) = n(A) + (n(B) – n(A∩B) + Y
X= 2% of X + 12% of X -1.35% of x + Y
X=0.02X+0.12X-0.0135X+Y
X=0.1265X+Y
Y=X-0.1265X
Y=0.8735X
Therefore the operation s that succeed and are free from infections is 0.8735 or 87.35%