Answer:
![m_2=2554.83\ kg](https://img.qammunity.org/2020/formulas/physics/college/r368m0o7mv9ohzpjevjv9d5ee887hb4j09.png)
Step-by-step explanation:
Given that,
Mass of the car,
![m_1=2200\ kg](https://img.qammunity.org/2020/formulas/physics/college/aulzocu7v2ne9psj23v7k6h7z1rqohql0p.png)
Initial speed of the car,
![u=3.6\ m/s](https://img.qammunity.org/2020/formulas/physics/college/plrivizx0d9ajq9yrlugyk9hras6s31pxh.png)
Final speed of the car,
![v=3.1\ m/s](https://img.qammunity.org/2020/formulas/physics/college/zzk7pvgedgnma62l1pun2jltviejdk8n2m.png)
To find,
The maximum mass of grain that it can accept.
Solution,
We know that according to the law of conservation of momentum, the initial momentum is equal to the final momentum.
![m_1u=m_2v](https://img.qammunity.org/2020/formulas/physics/college/p1fsy4aena4z5tps88nh5bdjzutuqwzx10.png)
![m_2=(m_1u)/(v)](https://img.qammunity.org/2020/formulas/physics/college/tt6cpfbtbphl28vhlxtzocbrpxvmfv1ntj.png)
![m_2=(2200* 3.6)/(3.1)](https://img.qammunity.org/2020/formulas/physics/college/58bxw9fdszo2m7pss002k24321j68cmtky.png)
![m_2=2554.83\ kg](https://img.qammunity.org/2020/formulas/physics/college/r368m0o7mv9ohzpjevjv9d5ee887hb4j09.png)
Therefore, the maximum mass of grain that it can accept is 2554.83 kg. Hence, this is the required solution.