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A traveller left town A at 6 :30 am and arrived at 3 :42 pm. how long was the journey ​

User Jooks
by
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2 Answers

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Answer: 9 hours and 12 minutes

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Step-by-step explanation:

Let's break the overall duration into these chunks

  • From 6:30 AM to 7:00 AM is 30 minutes
  • From 7:00 AM to 12:00 PM noon is 5 hours (since 12-7 = 5)
  • From 12:00 PM noon to 3:00 PM is 3 hours
  • From 3:00 PM to 3:42 PM is 42 minutes

Let's add up the minutes portions first

30+42 = 72 minutes

This is over 60 minutes, so we'll rewrite it like this

72 min = 60 min + 12 min = 1 hour, 12 min

The "12 min" is part of the final answer.

The "1 hour" will carry over.

The hours portions of 5 and 3 add to 8. Then tack on that 1 extra hour to get 8+1 = 9 hours.

Overall, the journey was 9 hours and 12 minutes

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Here's another approach:

The 12 hour time value of 3:42 PM is the same as 1542 in military or 24 hour time format. To convert any PM time to military time, add 12 to the hours portion (so 3+12 = 15 for instance). The minutes stays the same.

Once the PM time value is in military time, we subtract the starting and ending values

1542 - 0630 = 0912

The first part "09" indicates "9 hours". The second part "12" indicates "12 minutes.

We arrive at the same duration of 9 hours and 12 minutes

Side note: This assumes that all of the traveling occurs on the same day.

User Panagiotis Lefas
by
5.6k points
4 votes

Answer

9 hours 12 minutes

Step by step explanation

(3 : 42 + 12:00)PM

= 15:42

15 : 42 - 6 : 30

= 9hrs 12 minutes

Hope it will help you

User VFragosop
by
5.3k points