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Solve the compound inequality 2x + 14 < 4 or x – 7 > 3 and Solve |2x – 3| = 11. Plz show your work

User Declan
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1 Answer

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Answer:

Explanation:

Answer:

Explanation:

2x + 14 < 4 , you will treat this as if you are solving algebraic equation with equality sign but be mindful not to change the inequality sign to equality sign.

Subtract 14 from both sides of the equation , we have

2x < 4 - 14

2x < - 10

divide both sides by 2

x < -5

you should notice that the inequality sign did not change , this is because we divided by positive 2.

(ii) x - 7 > 3

Add 7 to both side

x > 10

(iii) considering the modulus symbol , it means the function inside the modulus could be either positive or negative , considering the positive aspect first , we have

2x - 3 = 11

2x = 11 + 3

2x = 14

x = 7

then considering the negative aspect , we have

- ( 2x - 3 ) = 11

- 2x + 3 = 11

-2x = 11 -3

-2x = 8

x = -4

User Nabb
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