Question

a stone slides in a straight line across a horizontal sheet of ice. I passes a pot A with a velocity of 14 m/s and the point B 2.5s later. Assuming the deceleration is uniform and AB=30m, find the deceleration .

Answer 1

The deceleration, a = -1.6 m/s²

Step-by-step explanation:

Given,

The initial velocity, u = 14 m/s

The time taken by the stone is, t = 2.5 s

The distance between the point, s = 30 m

Using the 2nd equations of motion

s = ut + 1/2 at²

∴ a = 2(s - ut)/t²

Substituting the values

a = 2(30 - (14)(2.5))/2.5²

= -1.6 m/s²

Hence, the deceleration of the stone, a = -1.6 m/s²