Answer: C.156
Explanation:
Given: Total seashells = 160
mean = 120
population standard deviation = 26 grams
The probability that the seashells weigh at least 68 grams :-'
![P(X\geq68) =P((x-\mu)/(\sigma)\geq(68-120)/(26))\\\\=P(z\geq-2)\\\\=P(z<2)\ \ \ [P(Z\geq-z)=P(Z<z)]\\\\= 0.9772\ \ \ [\text{By p-value table}]](https://img.qammunity.org/2022/formulas/mathematics/college/wcfimqzphq6lku1mvcjng8gbf8eoxjg7g8.png)
Total seashells weigh at least 68 grams = 0.9772 x 160 = 156.352≈ 156
Hence, the correct option is C.156