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Counterweight required for the boom to be balanced ​

Counterweight required for the boom to be balanced ​-example-1
User Shonni
by
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1 Answer

3 votes

Answer:

2400 N

Step-by-step explanation:

When the boom is balanced, N = 0.

Sum of the torques about the pivot:

∑τ = Iα

-W (0.5) + F (3.0) = 0

0.5 W = 3.0 F

W = 6.0 F

Given F = 400 N:

W = 2400 N

User Gandalf The White
by
6.7k points