Question

athlete swims the length of 50m pool in 20sec and moves the return trip to the starting position in 22 sec. find the average velocity and speed . a) in the first half of the swim b) in the second half of the swim c) in the total trip. help me pls i need help!!!!​

Answer 1

Step-by-step explanation:

Average velocity is displacement over time.

Average speed is distance over time.

a) In the first half of the race, the displacement is 50m, and the distance is also 50m.

v = 50m / 20s = 2.5 m/s

s = 50m / 20s = 2.5 m/s

b) In the second half of the race, the displacement is -50m. The distance is 50m.

v = -50m / 22s = -2.27 m/s

s = 50m / 22s = 2.27 m/s

c) In the total trip, the displacement is 0m. The distance is 100m.

v = 0m / 42s = 0 m/s

s = 100m / 42s = 2.38 m/s

Answer 2

1. 2.5 m/s

2. 2.27 m/s

3. 2.38 m/s

Step-by-step explanation:

physics my dude