Question

If 9.96 L of gas at 13°C and 2.28 atm is compressed at a pressure of 133 atm and 29°C, calculate the

Answer 1

V₂ = 0.18 L

Step-by-step explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 9.96 L

Initial pressure = 2.28 atm

Initial temperature = 13 °C (13 +273 = 286 K)

Final temperature = 29 °C (29 +273 = 302 K)

Final volume = ?

Final pressure = 133 atm

Formula :

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂ /T₁P₂

V₂ = 2.28 atm × 9.96 L × 302 k /286 K × 133 atm

V₂ = 6858.1 L /38038

V₂ = 0.18 L