Question

A 6-pack of canned drinks is to be cooled from 19°C to 3°C. The mass of each canned drink is 0.355 kg. The drinks can be treated as water, and the energy stored in the aluminum can itself is negligible. The amount of heat transfer from the six canned drinks is _____ kJ.

Answer 1

Answer: 143.1KJ

Step-by-step explanation:

Heat Capacity is defined as the amount of heat required to raise the temperature of a whole body by 1Kelvin.

Heat capacity Q = mct

m= mass of the body = 6×0.355kg=2.130kg (since we have 6packs of canned drinks)

c=specific heat capacity =4200J/NGK

t=change in temperature (final - Initial)= 19°C-3°C=16°C

imputing this values in the formula;

Heat capacity Q = 2.130×4200×16

= 143,136J = 143.1KJ