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Suppose a poll is taken that shows that 795795 out of 15001500 randomly​ selected, independent people believe the rich should pay more taxes than they do. Test the hypothesis that a majority​ (more than​ 50%) believe the rich should pay more taxes than they do. Use a significance level of 0.05.

User Doa
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Answer:

Yes. more than 50% is true.

Explanation:

Given that a poll is taken that shows that 795 out of 1500 randomly​ selected, independent people believe the rich should pay more taxes than they do.

Sample proportion p =
(795)/(1500) =0.53

Sample size n = 1500

Hypotheses would be


H_0: p = 0.50\\H_a: p >0.50

(Right tailed test at 5% significance level)

Std error of proportion =
\sqrt{(P(1-P))/(n) } =\sqrt{(0.5(1-0.5))/(1500) } \\=0.0129

Proportion difference = p-P =
0.53-0.5=0.03

Test statistic= p diff/std error =
(0.03)/(0.0129) \\=2.33

p value <0.05

Hence reject null hypothesis

There is significant difference in the two proportions and hence a majority​ (more than​ 50%) believe the rich should pay more taxes than they do is supported by statistical evidence.

User Xenon Kfr
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