Register
Hannah has information about an object in circular orbit around Earth. mEarth = 6.0 × 1024 kg G = 6.67 × 10–11 StartFraction m Superscript 3 Baseline over kilograms times s Superscript 2 Baseline EndFraction.
154k views
1 vote
Hannah has information about an object in circular orbit around Earth.

mEarth = 6.0 × 1024 kg

G = 6.67 × 10–11 StartFraction m Superscript 3 Baseline over kilograms times s Superscript 2 Baseline EndFraction.

What additional information does Hannah need in order to calculate the tangential speed of the orbiting object?

the mass of the orbiting object
the distance of the orbiting object to Earth
the orbital period of Earth
the radius of Earth

User MrYogi
by
5.5k points

2 Answers

3 votes

Answer:

The distance of the orbiting object to Earth

Step-by-step explanation:

The distance will help her find the speed.

User Elliot Vargas
by
5.8k points
6 votes

Answer:

B on edge

Step-by-step explanation:

User Patrick Williams
by
6.0k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.6m questions

7.3m answers

Other Questions

Which of these structures is primarily responsible for the enzymatic breakdown of a large molecules in the cell?
What are some common signs and symptoms of mental health disorders?
A state of joyful activity in which the subject performs an action effortlessly and skillfully is known as a(n) __________.
!! Earth Science!! Carbon dioxide is normally approximately 2% fraction of the air in the atmosphere. The reason carbon dioxide is considered a pollutant is because... a) Carbon dioxide levels are much
Which statement best describes the life cycle of plants such as ferns? a. Different plants have a different number of phases in their life cycle. b. Plants have a single life cycle and are entirely haploid.
Link Copied!