2 Answers

Juancarlos · Answer 1 · 2020-12-07T18:03:25+0000

The slope-intercept form of the equation of a line that passes through (5, -4) and has a slope of `3/4 is
y = (3)/(4)x + (-31)/(4)

Solution:

Given that line passes through (5, -4)

Slope "m" =
(3)/(4)

We have to find the slope intercept form

The slope intercept form is given as:

y = mx + b ---- eqn1

where "m" is the slope of the line and "b" is the y-intercept

Here in this sum m =
(3)/(4)

Calculating y-intercept:

Substitute (x, y) = (5, -4) and "m" value in eqn 1, we get

$\begin{array}{l}{-4=(3)/(4)(5)+b} \\\\ {-4=(15+4 b)/(4)} \\\\ {-16=15+4 b} \\\\ {4 b=-31} \\\\ {b=(-31)/(4)}\end{array}$

Now eqn 1 becomes,

y = (3)/(4)x + (-31)/(4)

Hence the slope intercept form is
y = (3)/(4)x + (-31)/(4)

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