Answer:
Explanation:
Given that the revenue reaches a maximum of about $ 59000 in April and a minimum of about $ 29000 in October. Suppose the months are numbered 1 through 12, where the months are numbered 1 through 12
Then minimum when x=10 and maximum when x = 4
Average = 44000 correspond to middle line
Amplitude =
![59000-44000 = 15000](https://img.qammunity.org/2020/formulas/mathematics/high-school/yh3v196k1dvvvc3uzadx9xhm0uk3x3skpt.png)
Hence the function roughly would be
![f(x) = 15000sin (B(X-C))+44000](https://img.qammunity.org/2020/formulas/mathematics/high-school/giuule704stf8im7ffsk4fjeqoyaq6fnax.png)
So we found out two values for A and D
To find values for B and C
The minimum of sine function corresponds to -pi/2 here it is 10 and maximum pi/2 here is 4.
Period = 12 months
So B = coefficient of X =
![(12)/(2\pi) \\=(6)/(\pi)](https://img.qammunity.org/2020/formulas/mathematics/high-school/14x5061wf0xb1cbvnkvud3vbpfwjcxlvl2.png)
Because symmetrical about x=7 we have x-7 with a negative sign since min atx =10
![f(x) =-15000sin (\pi)/(6) (x-7)+44000](https://img.qammunity.org/2020/formulas/mathematics/high-school/v024cms7n4hbbku2pcfarn1omafder4d3r.png)