Answer:
Explanation:
Given that about 24% of the Canadian population over 15 years of age are first generation; that is, they were born outside Canada.
X - first-generation Canadians in random samples of 1000 persons over 15 should therefore vary with the binomial (n = 1000, p = 0.24) distribution.
a) Mean of X =
![E(x) = np = 240](https://img.qammunity.org/2020/formulas/mathematics/college/c4ainip6ci6d5s4bs7igdgkxwj51ui778v.png)
Var(x) =
![npq = 182.4](https://img.qammunity.org/2020/formulas/mathematics/college/5fbqg0xgywnl0gu2qafcxgwpjc1heu7yz9.png)
Standard deviation =
![√(182.4) =13.51](https://img.qammunity.org/2020/formulas/mathematics/college/1mc7o8fbkih6ektd1jv46pw1000zwlagjq.png)
b) When approximated to normal this variable X will be normal
we check whether np and nq are greater than 5.
Here we find both are greater than 5. So binomial to normal approximation can be done.
X is N(240, 13.51)
the probability that the sample will contain between 210 and 270 first-generation Canadians
With continuity correction this equals
![P(209.5<X<270.5)\\= P((209.5-240)/(13.51) <Z<(270.5-240)/(13.51))\\=P(-2.26<Z<2.26)\\=2(0.4881)\\= 0.9762](https://img.qammunity.org/2020/formulas/mathematics/college/ghksslxj3intjiatp216gyrsx5o7mlzjrh.png)