Answer:
0.4082
Explanation:
Given that the number of customers received by a drive-through pharmacy on Saturday mornings between 8:00 AM and 9:00 AM has a Poisson distribution with λ (Lambda) equal to 1.4.
X has Poisson mean=1.4
the probability of getting at least 2 customers between 8:00 am and 9:00 am in the morning
=
![P(X\geq 2)\\=0.4082](https://img.qammunity.org/2020/formulas/mathematics/high-school/i9zgeap0frl9k8r5k44uik108zgss9zwe8.png)
Required probability = 0.4082