109k views
2 votes
A two-phase mixture of water and steam with a quality of 0.63 and T = 300F expands isothermally until only saturated vapor remains. The initial volume is 0.114 ft3 . During the process, 16.2 Btu of heat are added. Find the work done. Also draw this process in the P-v space indicating the initial and final states with respect to the liquid-vapor dome.

1 Answer

4 votes

Answer:

Step-by-step explanation:

Hello!

To solve this problem you must follow the following steps, which are fully registered in the attached image.

1. Draw the complete outline of the problem.

2. Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)

through prior knowledge of two other properties.

3. Use temodynamic tables to find the density of water in state 1, by means of temperature and quality, with this value and volume we can find the mass.

3. Use thermodynamic tables to find the internal energy in state 1 and two using temperature and quality.

4. uses the first law of thermodynamics that states that the energy in a system is always conserved, replaces the previously found values ​​and finds the work done.

5. draw the pV diagram using the 300F isothermal line

A two-phase mixture of water and steam with a quality of 0.63 and T = 300F expands-example-1
User An
by
5.3k points